63-25x+2x^2=0

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Solution for 63-25x+2x^2=0 equation: 



63-25x+2x^2=0

a = 2; b = -25; c = +63;
Δ = b2-4ac
Δ = -252-4·2·63
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-11}{2*2}=\frac{14}{4}
=3+1/2
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+11}{2*2}=\frac{36}{4}
=9
$

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